page1947 Rings Matthias Lorentzen...mattegrisenforlag.com
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scroll down to the question and click the correct Answer button.
Question
Based on this part of the proof,what does it mean that
`alpha` is algebraic over `F(beta)`:
A) `alpha` does not fit any polynomial, and `F(alpha , beta)`
is just F(beta) with `alpha` added freely.
B) `alpha` fits a polynomial with coefficients in `F(beta)`,
and `F(alpha , beta)` grows a fixed amount over `F(beta)`
?
